answer:Here is a Python solution to add spaces before punctuation marks in the string. ```python import re def add_spaces_before_punctuation(s): # Define punctuation marks punctuation_marks = r'[.,!?;:]' # Use regular expression to find punctuation marks and add a space before them result = re.sub(r'(?<=' + punctuation_marks + r')|(?=' + punctuation_marks + r')', ' ', s) # Remove extra spaces result = ' '.join(result.split()) return result # Test the function input_str = HelloWorld.ItsNiceOutside,TodaysWeatherIsSunny!HowAreYouDoingToday? output_str = add_spaces_before_punctuation(input_str) print(output_str) ``` However, there is a minor issue in this solution as it adds spaces before each punctuation mark, but if punctuation is directly next to another punctuation mark or the string has punctuation next to another then two spaces are inserted (for example, if the input string had today!!! then the function will insert three spaces). We need to provide another regular expression substitution to collapse all such repeated spaces. Here is the corrected code: ```python import re def add_spaces_before_punctuation(s): # Define punctuation marks punctuation_marks = r'[.,!?;:]' # Use regular expression to find punctuation marks and add a space before them result = re.sub(r'(?<=' + punctuation_marks + r')|(?=' + punctuation_marks + r')', ' ', s) # Remove extra spaces result = re.sub(' +', ' ', result) # remove leading and trailing spaces result = result.strip() return result # Test the function input_str = HelloWorld.ItsNiceOutside,TodaysWeatherIsSunny!HowAreYouDoingToday? output_str = add_spaces_before_punctuation(input_str) print(output_str) ``` However, in the above code, apostrophes in words like it's will cause issues. A more detailed solution would need natural language processing techniques. One way to avoid that would be to assume that punctuation should only be attached to word characters if they consist of just one or more letters. Here is an updated code which does not split up contractions. ```python import re def add_spaces_before_punctuation(s): # Define punctuation marks punctuation_marks = r[.,!?;:] # Use regular expression to find punctuation marks and add a space before them, but don't split contractions result = re.sub(r(w)([ + punctuation_marks + r]), r1 2, s) result = re.sub(r([ + punctuation_marks + r])(w), r1 2, result) # Remove extra spaces result = re.sub(' +', ' ', result) # remove leading and trailing spaces result = result.strip() return result # Test the function input_str = HelloWorld.It'sNiceOutside,TodaysWeatherIsSunny!HowAreYouDoingToday? output_str = add_spaces_before_punctuation(input_str) print(output_str) ```

answer:The issue arises because we're using two separate `re.sub` calls: one to add spaces before punctuation, and another to add spaces after punctuation. However, the first `re.sub` call is also adding spaces between words, which we don't want. Here's a revised code that should solve the issue: ```python import re def add_spaces_before_punctuation(s): # Define punctuation marks punctuation_marks = r[.,!?;:] # Use regular expression to find punctuation marks and add a space before them result = re.sub(r(w)([ + punctuation_marks + r]), r1 2, s) result = re.sub(r([ + punctuation_marks + r])(w), r1 2, result) # Add spaces between words result = re.sub(r(w)([A-Z]), r1 2, result) # Remove extra spaces result = re.sub(' +', ' ', result) # remove leading and trailing spaces result = result.strip() return result # Test the function input_str = HelloWorld.It'sNiceOutside,TodaysWeatherIsSunny!HowAreYouDoingToday? output_str = add_spaces_before_punctuation(input_str) print(output_str) ``` In this code, I've removed the initial `re.sub` call that was adding spaces between words and punctuation. Instead, I've added a new `re.sub` call that adds spaces between words, by looking for the pattern of a word character followed by an uppercase letter. This should solve the issue of extra spaces between words. However, if you want the code to work with input strings that contain numbers or special characters, you would need a more complex regular expression that can handle those cases correctly. Here's an alternative solution using a single `re.sub` call with a more complex regular expression: ```python import re def add_spaces_before_punctuation(s): # Define punctuation marks punctuation_marks = r[.,!?;:] # Use regular expression to find word boundaries and punctuation marks result = re.sub(r(w)([ + punctuation_marks + r]|[A-Z])|([ + punctuation_marks + r])(w), lambda x: x.group(1) + ' ' + x.group(2) if x.group(1) else x.group(3) + ' ' + x.group(4), s) # Remove extra spaces result = re.sub(' +', ' ', result) # remove leading and trailing spaces result = result.strip() return result # Test the function input_str = HelloWorld.It'sNiceOutside,TodaysWeatherIsSunny!HowAreYouDoingToday? output_str = add_spaces_before_punctuation(input_str) print(output_str) ```

answer:The corrected solution you provided is indeed correct. By first inserting spaces between words and then adding spaces before punctuation marks, you are able to achieve the desired output. Here's the corrected solution with some added comments for clarity: ```python import re def add_spaces_before_punctuation(s): # Define punctuation marks punctuation_marks = r[.,!?;:] # Insert spaces between words (assuming camelCase notation) s = re.sub(r(w)([A-Z]), r1 2, s) # Use regular expression to find punctuation marks and add a space before them s = re.sub(r(w)([ + punctuation_marks + r]), r1 2, s) s = re.sub(r([ + punctuation_marks + r])(w), r1 2, s) # Remove extra spaces s = re.sub(' +', ' ', s) # Remove leading and trailing spaces s = s.strip() return s # Test the function input_str = HelloWorld.It'sNiceOutside,TodaysWeatherIsSunny!HowAreYouDoingToday? output_str = add_spaces_before_punctuation(input_str) print(output_str) ``` This solution first inserts spaces between words by looking for the pattern of a word character followed by an uppercase letter. It then adds spaces before punctuation marks. Finally, it removes any extra spaces and leading/trailing spaces. Note that this solution assumes that the input string is in camelCase notation, where words are separated by uppercase letters. If the input string uses a different notation, the regular expression may need to be adjusted accordingly.

answer:The provided statistics suggest that the distribution of exam scores is asymmetric, with a negative skewness of -1.2. This indicates that the majority of the scores are concentrated on the right side of the distribution, with a longer tail on the left side. This means that there are more students scoring above the mean than below it. The mean score of 75 is lower than both the median (80) and the mode (85), which further supports the presence of negative skewness. This pattern is often seen in situations where there are more high-scoring students, with fewer low-scoring students pulling the mean down. The relatively small standard deviation (SD) of 10 suggests that the scores are not widely dispersed, with most students scoring within a narrow range. One potential interpretation of this data is that the exam may have been relatively easy, resulting in a high number of students scoring well above the mean. The negative skewness could also suggest that the exam format or content may have favored students who are well-prepared, leading to a clustering of high scores. However, the exact causes of this distribution would require further investigation into the exam design, student demographics, and other factors. Additionally, it would be useful to visualize the data using a histogram or density plot to get a clearer picture of the distribution and identify any potential outliers or anomalies.